RESEARCH / Focused target
The Arrow Patterns (12; 3 → 3) and (23; 1 → 1) Are Arrow-Wilf-Equivalent
RELEASED FOUNDATIONS / PROPOSED CONNECTION
Research connections
All source anchors (1)
- D5/S3/Combinatorics/ArrowWilfEquivalence.resultAbsent from this graph
Problem
The question
Robin D.P. Zhou and Xinyang Yu, Arrow-Wilf equivalences and enumerative results for short arrow patterns, arXiv:2609.29392v1, Section 7:
We have computed the avoidance counts for the arrow patterns (12; 3 → 3) and (23; 1 → 1) and found that the resulting sequences agree for all values of n tested. This suggests that these two patterns may be arrow-Wilf-equivalent. However, the explicit formulas we obtained for the two sequences are quite different in form, and we have not been able to establish the equivalence by a direct bijection or by any other method. We leave this as an open problem.
Arrow-Wilf equivalence means |S_n(12; 3 → 3)| = |S_n(23; 1 → 1)| for every n ≥ 1, with containment of
an arrow pattern as defined in Section 1 of the paper through π̂ = θ⁻¹(π).
Motivation
Our foothold
The frozen theorem D5/S3/Combinatorics/ArrowWilfEquivalence.result proves the equivalence for every
n ≥ 1. It is the equinumerosity the authors observed numerically and could not prove, and it relates
a class described through the largest fixed point of π̂ to a class described through the smallest one.
Gap
Missing bridges
Issue 9847 records the screen made before the work. The arXiv record has only v1; searches by title,
arXiv number and the two pattern names found no later proof; google-deepmind/formal-conjectures and
conjectures.io have no entry. Nothing under Problems/, D5/ or Library/, and no entry of the three
screening records, concerns this paper.
Route
Proposed approach
fis a fixed point ofπ̂exactly whenfis a left-to-right maximum ofπfollowed by a larger entry or by the end. Henceπavoids(12; 3 → 3)iff the entries below every fixed point appear in decreasing order, and avoids(23; 1 → 1)iff the entries above every fixed point appear in decreasing order.- Decomposing by the largest fixed point gives the count of Theorem 3.1, and decomposing by the smallest fixed point gives the count of Theorem 5.5; both decompositions are explicit bijections with decorated objects built from a derangement, a subset and a weak composition.
- With
E_n = Σ_{p=0}^{n−1} Σ_{i=0}^{p} (−1)^i (p!/i!) C(n−i−1, p−i), the first correction term equalsE_nafter the reindexingn − m = k + r,m = h + r + 1, which turns the binomial product into a trinomial coefficient, and the finite negative-binomial expansion of(1 − z − z²)^{−(k+1)}. The second correction term equalsE_nafter the substitutionk = m − 1 − r, the inclusion–exclusion formula ford_kand a hockey-stick summation; its boundary termd_{n−1}is the termp = n − 1ofE_n. - Both counts equal
d_n + E_n.
Falsifier
What would falsify this route
The statement would fail if some n had different avoidance counts. It would fail to be the paper's
statement if π̂ were read with cycles cut at left-to-right minima, or if containment ignored the order of
the selected values; the formal definitions follow Section 1 literally and agree with an independent
brute-force implementation on every permutation with n ≤ 7.
Evidence
Evidence to collect
Brute-force enumeration from the Section 1 definitions gives 1, 2, 5, 17, 75, 412, 2707, 20657 for both
classes at n = 1, …, 8, matching both formulas. The two formulas and d_n + E_n agree for every
1 ≤ n < 120, and every intermediate identity of the route was checked for n ≤ 60.
Triage
Scope assessment
theorem; Tier 1 open problem stated at the end of a 2026 paper, preregistered in issue 9847 before the
work. The computational use is none: the delivered statement is universally quantified over every
n ≥ 1, and no declaration is a bounded enumeration, a checker, a numeric reduction or a certified
instance.
ASSUMED-UNVERIFIED
Unverified assumptions
The literature screen is bounded to the sources named above; the paper was one day old when screened, so no worldwide priority claim is made. No direct bijection between the two classes is given; the equivalence passes through the common signed sum.