RESEARCH / Focused target
Local-channel monotonicity of Rényi conditional quantum mutual information
RELEASED FOUNDATIONS / PROPOSED CONNECTION
Research connections
All source anchors (1)
- D5/S3/Quantum/Information/RenyiCMILocalChannelRefutation.resultAbsent from this graph
Problem
The question
K. P. Seshadreesan, M. Berta, M. M. Wilde, Rényi squashed entanglement, discord, and relative entropy differences, §3, Conjecture 1:
Conjecture 1 The Rényi conditional quantum mutual information obeys monotonicity with respect to CPTP maps on system A, i.e., for ρABE ∈ S(HABE) and α ∈ (0, 1) ∪ (1, 2], Iα(A; B|E)ρ ≥ Iα(A′; B|E)τ, where τA′BE ≡ MA→A′(ρABE) and MA→A′ is a CPTP map acting on system A alone.
Equation (3.18) and the source's hypothesis statements appear in the literature note. Issue #16068 preregisters the witness.
Motivation
Our foothold
The paper uses local-channel monotonicity to obtain LOCC monotonicity for its Rényi squashed entanglement. Conditional correlation measures must distinguish monotonicity on the two unconditioned systems when their defining formula is asymmetric.
Gap
Missing bridges
Equation (3.18) has established monotonicity on $B$. The conjecture requires monotonicity on $A$ for the same expression and parameter range.
Route
Proposed approach
Write $M(p,q,s;u,v)$ for the real Hermitian matrix on $AE$ with rows $[p,0,0,q]$, $[0,u,0,0]$, $[0,0,v,0]$, $[q,0,0,s]$ in the order $00,01,10,11$. The state has classical $B$ and blocks $X_0=M(13,8,7;13,39)/144$, $X_1=M(7,8,13;39,13)/144$. Both blocks are positive definite: the coupled corner has positive trace and positive determinant $27/144^2$, and the other entries are positive. The trace is one. Dephasing $A$ uses $K_0=\operatorname{diag}(1,0)$ and $K_1=\operatorname{diag}(0,1)$.
The input marginal is $S=M(5,4,5;13,13)/36=H^2$, $H=M(2,1,2;\sqrt{13},\sqrt{13})/6$ and $H^{-1}=M(4,-2,4;6/\sqrt{13},6/\sqrt{13})$. The $E$ marginal is $1/2$ times the identity. At $\alpha=2$, the matrix under the final square root is $\operatorname{diag}(9,1,1,9)/64$, with square-root trace one. After dephasing it is $\operatorname{diag}(377,57,57,377)/2880$. The square-root trace exceeds one; equivalently the output is $\log((217+\sqrt{21489})/360)>0$, while the input is zero.
Falsifier
What would falsify this route
A failure of positivity, normalization, Kraus completeness, the partial traces, or either CFC power identity would invalidate this witness. A different Rényi CMI definition requires a separate settlement.
Evidence
Evidence to collect
The Lean module defines equation (3.18), its finite-dimensional claim and the
explicit witness, and proves result : ¬ claim. It verifies positive semidefiniteness,
trace one, Kraus completeness, the channel output, the marginals and the CFC power
identities. The input value is zero and the output value is strictly positive.
The latter proof bounds the square-root trace
$2\sqrt{377/2880}+2\sqrt{57/2880}>1$; elementary square-root and logarithm
identities give the equivalent expression $\log((217+\sqrt{21489})/360)$.
The axiom closure is exactly propext, Classical.choice and Quot.sound;
there is no sorry or native_decide.
The registered low-alpha continuation
Issue #17673
registers the remaining assertion with exactly $0<\alpha<1$ and the same
frozen mpow, renyiCMI and applyA definitions. The candidate
RenyiCMILowAlphaRefutation keeps the literal types claim : Prop and
result : Not claim. Its intended witness is $\alpha=1/2$ and
$t=2^{-30}$, with input dimensions $(3,2,2)$ and output dimensions $(2,2,2)$.
Write $H=\begin{pmatrix}0&1\1&0\end{pmatrix}$ and $R_0=\operatorname{diag}(16,1)/68$, $R_1=\operatorname{diag}(1,16)/68$, $R_2=I/4$. In the carrier $((A\times B)\times E)$, the candidate input is diagonal in $A,B$, with $E$ blocks $\rho_{a,b}=(R_a+(-1)^b t X_a)/2$, where $X_0=X_1=H$ and $X_2=-6H$. The three rectangular Kraus matrices are $K_j=|f(j)\rangle\langle j|$, with $f(0)=f(1)=0$ and $f(2)=1$. Thus their adjoint products sum to $I_3$, and the channel output has $E$ blocks $(I/4+2(-1)^btH)/2$ and $(I/4-6(-1)^btH)/2$. The input $AE$ marginal has diagonal blocks $R_0,R_1,R_2$; the output $AE$ marginal is $I_4/4$, and both $E$ marginals are $I_2/2$.
The matrix bridge uses a positive square-root certificate. For $M=\begin{pmatrix}a&u\u&b\end{pmatrix}>0$, put $d=\sqrt{ab-u^2}$ and $g=\sqrt{a+b+2d}$. The certificate $S=(M+dI)/g$ satisfies $S>0$ and $S^2=M$; CFC square-root uniqueness identifies the actual half power with $S$. Positive fourth-root certificates identify the $AE$ quarter powers, and an inverse certificate identifies the $E$ negative quarter power. This retains the order of multiplication and partial trace in equation (3.18).
Put $x=t^2$, $r=\sqrt{1-289x}$, $s=\sqrt{17+8r}$, $p=\sqrt{1-64x}$, $q=\sqrt{1-576x}$, $m=\sqrt{(1+p)/2}$, $n=\sqrt{(1+q)/2}$, $A=5(s^2+9)/(34s)$ and $B=4/s$. The proposed exact evaluations are $Z_{\rm in}=(A+n)^2/4+4x(B-3/n)^2$ and $Z_{\rm out}=(m+n)^2/4+4x(1/m-3/n)^2$, with the corresponding CMI values $-\log Z_{\rm in}$ and $-\log Z_{\rm out}$. Their difference factors as
$$ Z_{\rm out}-Z_{\rm in} =\frac{(m-A)(m+A+2n)}4 +4x(1/m-B)(1/m+B-6/n). $$
The abstract radical certificate bounds this expression by $-(473/1000)x$ for $0<x\le10^{-8}$ under the displayed radical identities and positivity assumptions. The fixed $x=2^{-60}$ is in this interval. After the exact matrix evaluations have been verified, $Z_{\rm out}>0$ and strict logarithm monotonicity give a strict increase in CMI.
Native verification boundary for the continuation
The complete low-alpha source has passed native Lean compilation against the
actual frozen imported module. This checks the state and channel certificates,
the ordered matrix bridge, the actual CFC powers, both exact CMI evaluations
and the strict comparison in the same whole-source proof. A separate native
check of the compiled artifact confirms that claim has the literal type
Prop and result has the literal type Not claim, with no universe
parameters. Both axiom closures are exactly propext, Classical.choice and
Quot.sound; the refutation is a closed kernel theorem.
Canonical selected build/report validation, Scribe emission and independent prefreeze review have passed. The scoped canonical deposit has frozen the exact low-alpha result. The existing Refuted resolution claim includes both the original alpha-two result and this low-alpha result. Final whole-delivery review and all applicable exact-head CI checks remain required before merge. The already accepted alpha-two result above is separate. The log-Euclidean, dual-J and other optimized quantities are not substitutions for this target.
Triage
Scope assessment
Tier 1: a named conjecture, preregistered in #16068. Admission basis:
open-problem-resolution; resolution: Refuted; result has
proof_shape: bind-only under normalization, with external open-problem admission.
What the refutation shows
- Proved (Lean): the three-qubit state with classical $B$ refutes Conjecture 1 under complete dephasing of $A$ at $\alpha=2$, $0\to\log((217+\sqrt{21489})/360)>0$. The explicit block factorizations also show that the state is faithful; strict positivity of the input state and the closed-form logarithm equality are algebraic consequences, while Lean certifies the positive semidefinite state and the strict increase.
- Reasoning: for positive definite $S_{AE}$ and a POVM ${E_b}$ on $E$, blocks $X_b=\sqrt S E_b\sqrt S$ give $I_2=0$. Here $E_0=\operatorname{diag}(3/4,1/4)$ and $E_1=\operatorname{diag}(1/4,3/4)$. An $A$-channel does not preserve this square-root factorization. The input has positive von Neumann CMI and is not a quantum Markov chain; the failure is specific to the Rényi formula.
- Computed: a rank-four variant with projective $E_b$ gives $0\to\log(10/9)$; numerical violations also occur at $\alpha=1.5$.
- Reasoning: the optimised sandwiched quantity of arXiv:1403.6102, Definition 19 and Remark 25, fails at $\alpha=1/2$ for this state, $0\to\log(648/(388+13(\sqrt{195}+\sqrt{35})))$. This quantity is not proved here.
- Consequences (reasoning): results that assume Conjecture 1, including LOCC monotonicity of this Rényi squashed entanglement and Consequences 3–4, lose that hypothesis. The $B$-side monotonicity proved in arXiv:1403.6102 is unaffected.
- Open: whether a modified Rényi CMI, such as the log-Euclidean quantities of Rubboli–Arqand–Wilde, arXiv:2609.34699, is the right replacement lies outside this settlement.
ASSUMED-UNVERIFIED
Unverified assumptions
Worldwide novelty and priority are not conclusions of the formal refutation. The numerical variants and the optimised sandwiched quantity are distinct from the theorem's CFC expression and remain outside its proof scope.