RESEARCH / Focused target
The minimum of purity plus time-reversal overlap
RELEASED FOUNDATIONS / PROPOSED CONNECTION
Research connections
All source anchors (1)
- D5/S3/Quantum/Entanglement/PurityTimeReversalOverlapMinimum.resultAbsent from this graph
Problem
The question
E. Serrano-Ensástiga, O. Giraud and J. Martin (arXiv:2507.12680, quant-ph;
Phys. Rev. A 113 (2026) 012415) bound the sector lengths of multiqubit states
through the reduced states ρ_A of a pure state and their time-reversed
partners ρ̃ = σ_y^{⊗k} ρ^* σ_y^{⊗k}, with the overlap R_ρ = Tr(ρ ρ̃).
Their Proposition 1 gives Tr(ρ_A²) + R_{ρ_A} ≥ 2^{−min(k, N−k)}, and they
state:
Let $A|\bar{A}$ be a bipartition of an $N$-qubit system into $k=|A|$ and $N-k=|\bar{A}|$ qubits. Then, the minimum of $\mathrm{Tr}(\rho_A^2) + R_{\rho_A}$ taken over all pure states $|\psi\rangle$ of the $N$-qubit system, is given by $\min_{|\psi\rangle} \big(\mathrm{Tr}(\rho_A^2) + R_{\rho_A}\big) = 2^{k-N}$ if $2k > N$, and $2^{-k + 1}$ if $2k \leq N$.
Issue #11730 fixes the reading: A is any set of k qubits with
1 ≤ k ≤ N − 1, a pure state is a unit vector of amplitudes on the 2^N
configurations, ρ_A is the partial trace over the other qubits, and the
minimum means a lower bound for every unit vector together with a unit vector
that attains it. The result proves the conjecture.
Motivation
Our foothold
The paper uses Tr(ρ_A²) + R_{ρ_A} to derive sector-length inequalities, and
the conjecture identifies the exact minimum of this quantity. The paper
proves the case k = 1 (the sum is identically 1) and reports the other
values from numerical optimization for up to ten qubits. The frozen
declaration
D5/S3/Quantum/Entanglement/PurityTimeReversalOverlapMinimum.result proves
the statement for every N and every bipartition.
Gap
Missing bridges
Issue #11730 preregisters the reading, the route and the literature check.
The two citing papers listed by Semantic Scholar (2604.09766, 2510.06602) do
not state the quantity, and arXiv searches for sector lengths after 2025-07
return works that neither cite the paper nor mention the time-reversed state.
The bound 2^{1−k} follows from the paper's own expansions of the purity and
of R_ρ in sector lengths (see Triage); this consequence is not drawn in the
paper, and the paper keeps the statement as a conjecture.
These readings are not-found-in-searched-scope; they do not establish an
exhaustive worldwide literature search, priority, or the absence of an
independent answer.
Route
Proposed approach
Write d = 2^k, r = 2^{N−k}, M the d × r matrix of amplitudes, so that
ρ_A = M Mᴴ with Tr ρ_A = 1, and Φ = Y M̄ with Y = σ_y^{⊗k}.
Yis Hermitian andY Y = 1, soρ̃_A = Φ Φᴴ,Tr ρ̃_A = 1, andΦᴴ Φis the entrywise conjugate ofMᴴ M.F = Tr(ρ_A²) + R_{ρ_A}equalsTr((MᴴM)²) + ‖Mᴴ Φ‖_F², andTr((MᴴM)²) = ‖MᴴM‖_F² ≥ |Tr MᴴM|²/r = 1/rby Cauchy–Schwarz on the diagonal. SoF ≥ 1/r.- For the Hermitian matrix
S = ρ_A + ρ̃_A,Re Tr S² = 2FandRe Tr S² = ‖S‖_F² ≥ |Tr S|²/d = 4/d. SoF ≥ 2/d. - If
2k ≤ N, an injection ofAinto the other qubits gives a maximally entangled state withρ_A = ρ̃_A = 1/dandF = 2/d. - If
2k > N, an injectionκof the other qubits intoAand a qubiti₀ofAoutside its image give a state withMᴴM = 1/r, soTr(ρ_A²) = 1/r, and withMᴴΦ = 0, because every entry contains the factorσ_y(0, 0) = 0ati₀; soF = 1/r. max(1/r, 2/d)is2^{k−N}when2k > Nand2^{1−k}when2k ≤ N.
Falsifier
What would falsify this route
The proof depends on σ_y in the time reversal: with the identity in its
place, ρ̃ = ρ̄, and for the state of step 5 the overlap equals
Tr ρ_A² = 1/r, so that state gives 2/r instead of 1/r. The trivial
bipartitions are excluded by the reading; for them max(1/r, 2/d) is also
the minimum (argument, not formalized): 1 for k = N ≥ 1, attained by a
configuration state, and 2 for k = 0, where the quantity is constant.
Evidence
Evidence to collect
Double-precision checks (issue #11730): 6 300 random states for
2 ≤ N ≤ 7 and every 1 ≤ k ≤ N − 1 never go below the claimed minimum
(smallest gap −1.1·10^{−15}), and the states of steps 4–5 reach it for
2 ≤ N ≤ 8.
The canonical source is
D5/S3/Quantum/Entanglement/PurityTimeReversalOverlapMinimum.lean. Its
public declarations are Outside, join, reducedState, sigmaYTensor,
timeReversed, purityPlusOverlap, conjecturedMin, claim and result;
reducedState is the frozen partialTraceRight of
D5/S3/Quantum/Information/PartialTraceMutualInformation, and σ_y is
i X Z for the frozen qubitX, qubitZ of D5/S3/Quantum/FiniteDimensional. The frozen module state has statement identity
sha256:87c4a3cae46e43203f1199d25a532167e7f7081fce502b7a09424e459bcfdfae.
The result declaration has statement identity
sha256:9593b9fd4c17d3f8f700bb16c229ae17c995960ac448b47ad392b40f7fbc2d3e.
The Freeze event is
sha256:0d70d7f5d6fdf9d03f26605b8ac9e940feeadc27899164f9c3e1a21cc4a347f9
and its project-level frozen prerequisites are these two modules. The proof
uses only the
standard axioms propext, Classical.choice and Quot.sound; no sorry,
native_decide, or new axiom.
Triage
Scope assessment
Tier 1 conjecture from a 2025 quant-ph paper, preregistered in issue #11730
before any Lean. theorem; resolution proved. The public theorem has
proof_shape: bind-only: the Frobenius identity, sq_sum_le_card_mul_sum_sq
and trace cyclicity give the two lower bounds, and coefficient computations
give the two explicit states; every step is a local have of result. There
is no escape witness. The admission basis is open-problem-resolution.
Utility none.
What the settlement shows
Proved (Lean): for every N and every set A of 1 ≤ k ≤ N − 1 qubits,
the minimum of Tr(ρ_A²) + R_{ρ_A} over pure states is
max(2^{1−k}, 2^{k−N}).
Source consequences (paper's Proposition 1, not formalized): its lower
bound 2^{−min(k, N−k)} is attained exactly when 2k > N; for
2 ≤ k ≤ N − k the minimum is twice that bound.
Mechanism (argument, not formalized): the paper's Eq. (trArA) gives
Tr(ρ_A²) = 2^{−k} Σ_m S_m(ρ_A) and R_{ρ_A} = 2^{−k} Σ_m (−1)^m S_m(ρ_A),
so Tr(ρ_A²) + R_{ρ_A} = 2^{1−k} Σ_{m even} S_m(ρ_A). With S_0 = 1 and
S_m ≥ 0 (the paper's Eqs. Eq.Trace1, Ineq.Sk) this is at least
2^{1−k}, with equality exactly when every even sector length
S_m(ρ_A), m ≥ 2, vanishes; the maximally mixed ρ_A of step 4 is such a
state. The bound 2^{k−N} is the purity of the reduced state of the smaller
part, Tr ρ_A² = Tr ρ_² ≥ 2^{−(N−k)}, together with R ≥ 0.
Not formalized (argument): when 2k > N, equality F = 2^{k−N} forces
ρ_A to have 2^{N−k} equal non-zero eigenvalues and its support to be
orthogonal to its image under the time reversal, as for the state of step 5.
ASSUMED-UNVERIFIED
Unverified assumptions
The published Phys. Rev. A text was not read, so it is unverified whether the conjecture was edited there. The bounded literature check does not establish exhaustive worldwide novelty, priority, or the absence of an independent answer. The Lean kernel does not authenticate the external source or its version history.