RESEARCH / Focused target
The most classical orthonormal basis of spin 3/2
RELEASED FOUNDATIONS / PROPOSED CONNECTION
Research connections
All source anchors (1)
- D5/S3/Quantum/Measurement/SpinThreeHalvesClassicalBasis.resultAbsent from this graph
Problem
The question
M. Rudziński, A. Burchardt and K. Życzkowski, Orthonormal bases of extreme quantumness, Quantum 8, 1234 (2024), arXiv:2306.00532v3, Conjecture 1:
The matrix $U_4^{c}$ given in (21), for which $\mathcal{B}_1=\frac{1}{9}$, leads to the most spin-coherent (classical) basis in $\mathcal{H}_4$.
Here $\mathcal{B}_1(U)$ is the mean, over the four basis vectors given by the columns of $U$, of the one-qubit anticoherence $\mathcal{A}_1(\psi) = 2[1 - \operatorname{tr}\rho_1(F\psi)^2]$, where $F$ sends a spin-3/2 state to the symmetric state of three qubits and $\rho_1$ is its one-qubit reduced state (Eqs. (8) and (12)–(15)). The verbatim statements are in the literature note.
Issue #18510 fixes the reading: 1/9 ≤ ℬ₁(U) for every U ∈ U(4), and the printed $U_4^c$ is unitary with ℬ₁ = 1/9. This is proved.
Motivation
Our foothold
A complete orthogonal measurement on a spin cannot consist of coherent states. ℬ₁ measures how far the best such measurement must stay from classical, and the source found its minimum for N = 4 only numerically, by imposing the symmetries of a random-walk optimum. The source settles N = 3 (Proposition 1) and the opposite extremum for N = 4 (Proposition 2).
Gap
Missing bridges
Issue #18510 records the literature check before any Lean:
- arXiv v3 is the latest version and keeps Conjecture 1;
- the seven arXiv citing works listed by Semantic Scholar cite the paper only for anticoherent states or bases, spin coherence or background, and none states or settles the minimum 1/9; the eighth listed citing work, a 2024 QISKit article, was not read;
- the repository had no record of the paper.
not-found-in-searched-scope.
Route
Proposed approach
Write J_x, J_y, J_z for the spin-3/2 matrices, p_i for the polarization of the column u_i of U and S(U) = Σ_i |p_i|².
- The Dicke bridge. The one-qubit reduced state of Fψ has Bloch vector 2p/3, so 𝒜₁(ψ) = 1 − 4|p|²/9 and ℬ₁(U) = 1 − S(U)/9. The claim becomes S(U) ≤ 8.
- Determinant one. Rescaling one column by a phase leaves every p_i unchanged, so U ∈ SU(4).
- A real six-frame. For U ∈ SU(4) the matrix of 2 × 2 minors, in a basis of Λ²ℂ⁴ fixed by a Hodge-type real structure, is real orthogonal.
- The transport. Since Σ_i p_i = 0, S = Σ_k |p₁ + p_{k+1}|². The one-body expansion of the lifted spin generators identifies each |p₁ + p_{k+1}|² with 2‖[X_k, Y_k]‖², where (s_k, X_k) and (t_k, Y_k) are frame vectors in ℝ ⊕ Sym₀(ℝ³).
- Böttcher–Wenzel. ‖[X, Y]‖² ≤ 2(‖X‖²‖Y‖² − ⟨X, Y⟩²), together with the frame identities ‖X_k‖² = 1 − s_k², ‖Y_k‖² = 1 − t_k², ⟨X_k, Y_k⟩ = −s_k t_k and Σ_k (s_k² + t_k²) = 1, gives S ≤ 8.
- Attainment. The polarizations of $U_4^c$ have squared length 2 and pairwise inner products −2/3, so S = 8.
Falsifier
What would falsify this route
The theorem would not settle the question if the module's quantities differed from the source's. The module takes:
- the normalized Dicke embedding sending the k-th basis vector (m = 3/2 − k) to the uniform superposition of three-bit strings with k ones, as in Eq. (8);
- the trace over the first two qubits, as in Eq. (12), and 𝒜₁ = 2(1 − tr ρ₁²), as in Eq. (14) at t = 1;
- the columns of U as the basis vectors, as in the source's convention $U_{ki} = \langle j, j+1-k|\psi_i\rangle$;
- Eq. (21) entry by entry, with ω₃ = e^{2πi/3} written as (−1 + i√3)/2.
Evidence
Evidence to collect
The canonical source is D5/S3/Quantum/Measurement/SpinThreeHalvesClassicalBasis.lean (743 lines).
- Definitions. It defines
dicke,reducedState,anticoherence,basisAnticoherence,classicalBasisandclaim, and provesresult : claim. - Reuse. It reuses:
- the spin matrices
Jx,Jy,JzofPrecessionSpinOneSeparableBound; - the compound matrices of
Schatten/CompoundMatrices; - the Frobenius norm and the Böttcher–Wenzel bound of
WeightedBotcherWenzel.
- the spin matrices
- Axioms. It uses only the standard axioms
propext,Classical.choiceandQuot.sound; nosorry,native_decide, or new axiom. - Escape registration:
Reg/D5/S3/Quantum/Measurement/SpinThreeHalvesClassicalBasis.lean(result,declared_validated).
Frozen state: Golden/Frozen/state/D5/S3/Quantum/Measurement/SpinThreeHalvesClassicalBasis.lean.json, statement sha256:cf869ff9b7dde4ab943b25cfccc33fe11e6fa481e51186bf799a42436b3bcccd.
Declaration statements:
result:sha256:f11b356fe67549611957675ad7e5faf42a26535d34852c6dbbc2a32edd0895e2;claim:sha256:1ff4fd0bf3a7a7f743ca38a81ac9edaf23de69dfe7185bec75ffec7a20289f67.
Triage
Scope assessment
Tier 1 conjecture of a 2023 paper (published 2024), preregistered in issue #18510 before any Lean.
theorem; resolution proved.
| declaration | proof_shape | escape_witness | admission_basis |
| --- | --- | --- | --- |
| result | bind-only | none: after inlining, the Dicke bridge, the compound-matrix frame, the transport and the Böttcher–Wenzel step are instantiations of existing lemmas and finite matrix identities | open-problem-resolution |
| dicke, reducedState, anticoherence, basisAnticoherence, classicalBasis, claim | bind-only | none | definitions used by claim |
| the polarization, frame, transport and attainment helpers (private) | bind-only (consumed on the proof path of result) | none | consumed helpers |
Every declaration is bind-only. The bind-only form is admitted under the open-problem-resolution basis of CLAUDE.md §3.2; no escape witness is claimed. The module is a general theorem over all of U(4) with its attainment, so utility is none. There is no digestion atom.
What the settlement shows
Proved by result: the minimum of ℬ₁ over all orthonormal bases of the spin-3/2 space is 1/9, attained by $U_4^c$.
Computed, not formalized (orchestrator, recorded in #18510):
- over 200 000 Haar-random unitaries S(U) ≤ 7.65, and 60 local ascents reach S = 8.000000000000;
- each step of the route holds numerically on 2000 random U ∈ SU(4).
Argued, not formalized.
- Mechanism. Λ²: SU(4) → SO(6) turns the four-vector problem into a six-frame of real symmetric 3 × 3 matrices, where the spin-2 part of Λ²(spin 3/2) is the traceless symmetric representation. Four coherent states would give S = 9. The orthogonality of the four vectors makes the transported vectors a real orthonormal six-frame: it gives the pairwise identities ‖X_k‖² = 1 − s_k², ‖Y_k‖² = 1 − t_k², ⟨X_k, Y_k⟩ = −s_k t_k and the completeness Σ_k (s_k² + t_k²) = 1, which together cost exactly one unit.
- Equality. Equality needs equality in Böttcher–Wenzel for each k, so the three commutators are extremal. This matches the regular tetrahedron of polarizations of $U_4^c$. Whether every minimizer is a rotation of $U_4^c$ up to phases and column order is not determined here.
- Scope. The argument uses SU(4) ≅ Spin(6) and does not extend directly to N ≥ 5; the source's numerical Conjectures 2 and 3 for N = 5, 6 are not addressed.
Effect on the paper. The numerically found basis $U_4^c$ is the global minimizer, so the most classical spin-3/2 measurement has mean anticoherence exactly 1/9, against the Haar mean 2/3 of the source's Eq. (31).
ASSUMED-UNVERIFIED
Unverified assumptions
The bounded literature check does not establish exhaustive worldwide novelty or priority. The statements in "Computed, not formalized" and "Argued, not formalized" are not formalized.