RESEARCH / Focused target
OEIS A396843: all coefficients are odd
RELEASED FOUNDATIONS / PROPOSED CONNECTION
Research connections
All source anchors (1)
- D5/S1/Recurrence/Invariants/CatalanCompositionSquareParity.catalan_uniqueAbsent from this graph
Problem
The question
OEIS A396843 defines A(x) = Sum_{n>=1} a(n)*x^n by
G.f. A(x) satisfies A( xA(x) - 3x*A(x)^2 ) = x^2.
Paul D. Hanna's comment of July 1, 2026 states, verbatim:
Conjecture: all terms are odd.
Motivation
Our foothold
The listed 23 coefficients are odd, but a finite computation does not prove the assertion for every positive index.
The existing catalan_unique theorem is a same-domain precedent for proving
formal-series identities by successive coefficient determination. The proof
below establishes the needed uniqueness directly and does not invoke that
theorem or a Catalan formula.
Gap
Missing bridges
Repository searches found no A396843 declaration. Pinned Mathlib provides formal power-series substitution and coefficient lemmas, but no theorem that directly solves this characteristic-two composition equation.
Route
Proposed approach
Reduce the defining equation modulo two. Write F for the reduced series and
H=x(F+F^2). The equation becomes F(H)=x^2. Its degree-two coefficient
gives coeff(1,F)^2=1, hence coeff(1,F)=1 in characteristic two.
Suppose two solutions agree below degree d. Their inner series agree below
degree d+1, and the difference of their degree-d+1 coefficients is the
difference of the degree-d coefficients of the original series. Since each
inner series is divisible by x^2, powers from the second onward gain two
further degrees. Comparing degree d+1 in the two compositions therefore
determines coefficient d uniquely. Induction proves uniqueness.
The geometric series S=x/(1+x)=x+x^2+x^3+... is a solution. Indeed,
x(S+S^2)=x^2/(1+x)^2 and substitution gives S(x(S+S^2))=x^2.
Uniqueness yields F=S, so every positive-degree coefficient reduces to one
modulo two and every corresponding integer coefficient is odd.
Falsifier
What would falsify this route
An integer formal power series with zero constant coefficient satisfying the stated equation and having an even positive-index coefficient would contradict the theorem.
Evidence
Evidence to collect
- Lean module:
D5/S1/Recurrence/Parity/CompositionalSquareAllOddCoefficients.lean. - Resolution declaration:
hanna_conjecture. - The proof imports only Mathlib formal power-series and finite-field results.
The exact statement is:
theorem hanna_conjecture (A : PowerSeries Z) (h0 : constantCoeff A = 0)
(hEq : A.subst (X * A - 3 * X * A ^ 2) = X ^ 2) :
forall n, 1 <= n -> Odd (coeff n A)
Triage
Scope assessment
theorem. The formal proof establishes the universal parity assertion from
the defining equation alone.
ASSUMED-UNVERIFIED
Unverified assumptions
The source wording, attribution, date, and numerical check were supplied by the implementation brief. Source-to-Lean identification is not a kernel-checked fact.