RESEARCH / Focused target
Mathar's linear recurrence for the A372991 factorial-quotient sequence
RELEASED FOUNDATIONS / PROPOSED CONNECTION
Research connections
All source anchors (1)
- The Factorial-Quotient Recurrence of OEIS A372991Released anchor
Problem
The question
OEIS A372991 NAME (Clark Kimberling, Jul 15 2024):
a(n) = (2n)!/(a(n-1)*a(n-2)), where a(0)=1, a(1) = 1.
FORMULA (for n ≥ 3):
Conjecture D-finite with recurrence a(n) -2n(2*n-1)*a(n-3)=0. - R. J. Mathar, Jul 16 2024
Motivation
Our foothold
This is a first-tier recent OEIS conjecture from 2024. The target is the universal recurrence, with KPI = open problems resolved.
Gap
Missing bridges
The supplied search reported no proof found: the search seat read the OEIS entry and revision history on 2026-09-08 and searched arXiv, MathOverflow, and GitHub by identifier. This Stage-B seat had no network access and did not independently repeat those readings or searches. No exhaustive literature or first-publication priority claim follows from that scope.
Route
Proposed approach
Define the sequence over the rationals, so division does not assume integrality. Two-step induction proves positivity. For n ≥ 3, the consecutive triple products a(n)a(n−1)a(n−2) = (2n)! and a(n−1)a(n−2)a(n−3) = (2n−2)! share two positive factors. Cancellation gives a(n)/a(n−3) = 2n(2n−1), equivalently Mathar's recurrence. Integrality follows by induction along residue classes mod 3, starting from a(0)=1, a(1)=1, and a(2)=24; the Lean proof implements this as strong induction on n.
Falsifier
What would falsify this route
A counterexample index n ≥ 3 for the defined sequence with a(n) ≠ 2n(2n−1)a(n−3) would contradict the assertion. The orchestrator's exact check is supporting evidence only, not a substitute for the unbounded proof.
Evidence
Evidence to collect
- Lean module:
D5/S1/Recurrence/Invariants/FactorialQuotientRecurrence.lean. - Main theorem:
mathar_recurrence. - Actual companions:
a_pos,triple_product, anda_integral. - The requested names
mathar_recurrence_one,altRowSum_succ_sub, andfib_cassini_twoare not declarations in this module; they are not claimed as proved companions or used as evidence for this resolution. - Axioms: std3 (
propext,Classical.choice,Quot.sound), exactly as reported for all four public theorems in the implementation seat's receipt. - The resolution claim is attached only to
mathar_recurrencein the Scribe source; finite checks do not carry the universal assertion.
Triage
Scope assessment
theorem. The formal proof establishes the displayed polynomial-coefficient
linear recurrence for every n ≥ 3. It also proves natural-number integrality
of every rationally defined term.
ASSUMED-UNVERIFIED
Unverified assumptions
The verbatim NAME and FORMULA quotes, attribution, and dates were supplied by the orchestrator. The OEIS revision history was read by the search seat, not this seat. The supplied literature scope was the OEIS entry and revision history read on 2026-09-08 plus identifier searches on arXiv, MathOverflow, and GitHub. This seat had no network access; later edits, literature outside that scope, and first-publication priority were not independently checked. Source-to-Lean identification is not a kernel-checked fact. The std3 report and prior compilation were supplied evidence; Stage B did not rerun them.