RESEARCH / Focused target
Barker's recurrence for crossing- and nesting-free labeled graphs
RELEASED FOUNDATIONS / PROPOSED CONNECTION
Research connections
All source anchors (1)
- Crossing- and Nesting-Free Labeled GraphsReleased anchor
Problem
The question
OEIS A326244, NAME:
Number of labeled n-vertex simple graphs without crossing or nesting edges.
COMMENTS:
Two edges {a,b}, {c,d} are crossing if a < c < b < d or c < a < d < b, and nesting if a < c < d < b or c < a < b < d.
FORMULA:
Conjectures from Colin Barker, Jun 28 2019: (Start)
G.f.: (1 - x)(1 - 4x) / (1 - 6x + 8x^2 - 4*x^3).
a(n) = 6a(n-1) - 8a(n-2) + 4*a(n-3) for n>2.
(End)
The entry line is _Gus Wiseman_, Jun 20 2019. The generating-function line
is the same third-order recurrence together with initial values 1, 1, 2; no
separate generating-function identity is claimed here.
Motivation
Our foothold
This 2019 OEIS conjecture asks for an exact unbounded recurrence for a literal class of labeled simple graphs. Proving it resolves the stated open problem without replacing the graphs by an auxiliary encoding in the public theorem.
Gap
Missing bridges
The 2026-09-13 search recorded on issue #7437 found zero relevant proof hits
on Crossref and OpenAlex. A GitHub claim-level search also found zero proofs;
exact-token results were sequence mirrors or programs that assumed the
recurrence. Marberg (2013) and de Mier (2006) study related crossing and
nesting classes, not this intersection count. The arXiv search is
ASSUMED-UNVERIFIED because the probe ended before preserving a complete
search receipt. This bounded search does not establish publication priority.
Route
Proposed approach
For an avoiding graph G, let A(G) be the vertices c such that every edge
whose right endpoint is greater than c is incident with c. Removing the
greatest vertex gives a bijection
avoiding(n+1) ≃ Σ_G P(A(G)).
The private restriction and gluing maps implement the two directions and
prove that the avoiding condition is preserved. If the chosen subset S has
size r, the allowed-set size after gluing is r+1 when S is empty, 2
when S is a singleton, and 1 when S has at least two elements. The proof
then uses the moments X, Y, and Z, with
X_(n+1) = Z_n,
Y_(n+1) = 2*Y_n + Z_n,
Z_(n+1) + 2*X_n = 2*Y_n + 4*Z_n.
Eliminating Y and Z yields the third-order recurrence for the literal
count a. All state machinery is private; only the source definitions and
the final recurrence form the public surface.
Falsifier
What would falsify this route
One index n > 2 for which the literal graph count differs from
6*a(n-1) - 8*a(n-2) + 4*a(n-3) would refute the result.
Evidence
Evidence to collect
- Lean module:
D5/S1/Words/Patterns/NoncrossingNonnestingGraphRecurrence.lean. - Main theorem:
barker_a326244. - Public definitions:
Crossing,Nesting,IsAvoiding, anda. - The theorem's axiom closure is std3:
propext,Classical.choice, andQuot.sound. - The orchestrator independently counted conflict-graph independent sets for
n = 0..7, obtaining1, 1, 2, 8, 36, 160, 704, 3088, exactly the values produced by the recurrence from initial values1, 1, 2. - The search seat exhaustively checked all
2,131,020graphs throughn = 7and reported zero mismatches.
The finite computations support the statement; the Lean proof establishes
the recurrence for every natural n > 2.
Triage
Scope assessment
theorem. The formal result proves Barker's recurrence for the exact labeled
graph class stated by OEIS A326244.
ASSUMED-UNVERIFIED
Unverified assumptions
The arXiv search was not independently completed by this seat. The source quotation, attribution, search-surface readings, related-literature scope, and supporting finite enumerations are external evidence rather than kernel-checked facts. No claim of exhaustive literature coverage, priority, or a separately formalized generating-function identity is made.