RESEARCH / Focused target
The A193020 plus-one eventual identity
RELEASED FOUNDATIONS / PROPOSED CONNECTION
Research connections
All source anchors (1)
- D5/S1/Words/EndpointShuffleSupport.resultAbsent from this graph
Problem
The question
OEIS A193020, revision 13, with the 2011 entry attribution to John W.
Layman, states the separate assertion a(2^k+1)=k^2 with its
sufficiently-large lower-bound caveat. Here a(n), for positive n, counts
DISTINCT output words obtained by shuffling the ordinary binary expansion
of n with itself. Each shuffle preserves the order within both copies;
different schedules producing the same word contribute only once.
The exact selected assertion is
$$\exists K\in\mathbb N,\quad 1\le K\ \land
\forall k\in\mathbb N,\quad K\le k\ \Longrightarrow\ a(2^k+1)=k^2.$$
This dossier anchors only that plus-one question. The other identities in A193020 are separate questions.
Motivation
Our foothold
The frozen theorem D5/S1/Words/EndpointShuffleSupport.result retains the
eventual assertion and supplies the uniform threshold K=1. Counting the
support of the shuffle language makes the distinction between output words
and interleaving schedules essential.
Gap
Missing bridges
The mathematical gap is an exhaustive description of the distinct support for an unbounded family of binary words. A finite sequence table or a count of labelled schedules does not give that description. The source and literature verification for this first-tier externally stated question is the bounded scope recorded with issue 23034. No claim of worldwide openness or publication priority follows from that scope.
Route
Proposed approach
For k at least one, the ordinary binary numeral of 2^k+1 is one, k-1 zeros, one. Write m=k-1. Every distinct self-shuffle of one, m zeros, one has the form
$$1,0^a,1,0^{(m-a)+(m-c)},1,0^c,1, \qquad 0\le a\le m,\quad 0\le c\le m.$$
The first two ones bound a by m; the last two bound c by m. There are 2m zeros altogether, fixing the middle gap. Conversely, label the copies A and B: take A's initial one and a zeros, B's initial one, the remaining m-a zeros from A and m-c zeros from B, A's final one, then B's c zeros and final one. This realizes every bounded pair while preserving both source orders.
The output word determines a and c, so the rectangle of pairs has no collisions. Its cardinality is (m+1)^2=k^2. Empty zero blocks are allowed, including m=0, so the argument applies from k=1 onward.
Falsifier
What would falsify this route
Refuting the selected eventual assertion would require counterexamples at arbitrarily large natural exponents: for every K at least one, some k at least K would have a(2^k+1) different from k^2. A single failure at k at least one would refute the stronger threshold-one conclusion, but would not by itself refute the eventual assertion. Matching a finite prefix does not prove either conclusion.
Evidence
Evidence to collect
D5/S1/Words/EndpointShuffleSupport.result has statement identity
sha256:f4c35407fff00d562c2aaec9ad687f4c2f754a1f8c46a0948d55d80a31cffec8.
It states the existential natural threshold and the universal tail
without additional mathematical hypotheses. Its proof chooses K=1.
The sequence definition uses the existing ordinary order-preserving
shuffle operation, then converts its output list to a finite set before
taking cardinality. For positive inputs, binaryWord uses the ordinary
most-significant-first binary numeral without leading zeros. Its empty
list at zero is a totalization outside the published positive-input
scope, and is not needed for the selected assertion. The accepted axiom
closure is propext, Classical.choice and Quot.sound.
Triage
Scope assessment
What the settlement shows
Proved: D5/S1/Words/EndpointShuffleSupport.endpoint_support_eq identifies
the entire distinct support with the two-gap rectangle for every natural
m. D5/S1/Words/EndpointShuffleSupport.endpointFamily_card proves the
rectangle's cardinality, and
D5/S1/Words/EndpointShuffleSupport.endpoint_self_shuffle_card gives
the exact count (m+1)^2. The decisive mechanism is the recoverability
of the two bounded outer gaps, with the middle gap fixed by conservation
of zeros.
Proved: D5/S1/Words/EndpointShuffleSupport.binaryWord_pow_add_one
connects that word family to every positive exponent. Together with the
support theorem, D5/S1/Words/EndpointShuffleSupport.result proves the
source's eventual identity with K=1. This is an exact unbounded family,
including the boundary k=1; it does not assert a threshold at k=0.
Open here: the other special-input identities posed in A193020 remain separate questions. In particular, the separate plus-two and minus-four questions receive no resolution from this claim. Other binary patterns need their own exhaustive support descriptions; the endpoint-word rectangle alone does not supply them. The selected conclusion can be used wherever this particular plus-one identity is a premise, but gives no automatic change to the entry's other assertions or their truth.
ASSUMED-UNVERIFIED
Unverified assumptions
The external source identity, revision-13 interpretation and literature
limits are those of the existing source verification associated with
issue 23034 and Library/Digit/layman2011a193020.md; no fresh external
source or literature search is asserted here. Later revisions, linked
material not read in that scope, worldwide openness and first-publication
priority are not certified. The source is credited to John W. Layman and
the OEIS contributors under CC-BY-SA-4.0. Only the separate plus-one
question is attached to the theorem's resolution claim.