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RESEARCH / Focused target

The A193020 plus-one eventual identity

Literature status: not recheckedRepository record: proved

RELEASED FOUNDATIONS / PROPOSED CONNECTION

Research connections

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Problem

The question

OEIS A193020, revision 13, with the 2011 entry attribution to John W. Layman, states the separate assertion a(2^k+1)=k^2 with its sufficiently-large lower-bound caveat. Here a(n), for positive n, counts DISTINCT output words obtained by shuffling the ordinary binary expansion of n with itself. Each shuffle preserves the order within both copies; different schedules producing the same word contribute only once.

The exact selected assertion is

$$\exists K\in\mathbb N,\quad 1\le K\ \land
\forall k\in\mathbb N,\quad K\le k\ \Longrightarrow\ a(2^k+1)=k^2.$$

This dossier anchors only that plus-one question. The other identities in A193020 are separate questions.

Motivation

Our foothold

The frozen theorem D5/S1/Words/EndpointShuffleSupport.result retains the eventual assertion and supplies the uniform threshold K=1. Counting the support of the shuffle language makes the distinction between output words and interleaving schedules essential.

Gap

Missing bridges

The mathematical gap is an exhaustive description of the distinct support for an unbounded family of binary words. A finite sequence table or a count of labelled schedules does not give that description. The source and literature verification for this first-tier externally stated question is the bounded scope recorded with issue 23034. No claim of worldwide openness or publication priority follows from that scope.

Route

Proposed approach

For k at least one, the ordinary binary numeral of 2^k+1 is one, k-1 zeros, one. Write m=k-1. Every distinct self-shuffle of one, m zeros, one has the form

$$1,0^a,1,0^{(m-a)+(m-c)},1,0^c,1, \qquad 0\le a\le m,\quad 0\le c\le m.$$

The first two ones bound a by m; the last two bound c by m. There are 2m zeros altogether, fixing the middle gap. Conversely, label the copies A and B: take A's initial one and a zeros, B's initial one, the remaining m-a zeros from A and m-c zeros from B, A's final one, then B's c zeros and final one. This realizes every bounded pair while preserving both source orders.

The output word determines a and c, so the rectangle of pairs has no collisions. Its cardinality is (m+1)^2=k^2. Empty zero blocks are allowed, including m=0, so the argument applies from k=1 onward.

Falsifier

What would falsify this route

Refuting the selected eventual assertion would require counterexamples at arbitrarily large natural exponents: for every K at least one, some k at least K would have a(2^k+1) different from k^2. A single failure at k at least one would refute the stronger threshold-one conclusion, but would not by itself refute the eventual assertion. Matching a finite prefix does not prove either conclusion.

Evidence

Evidence to collect

D5/S1/Words/EndpointShuffleSupport.result has statement identity sha256:f4c35407fff00d562c2aaec9ad687f4c2f754a1f8c46a0948d55d80a31cffec8. It states the existential natural threshold and the universal tail without additional mathematical hypotheses. Its proof chooses K=1.

The sequence definition uses the existing ordinary order-preserving shuffle operation, then converts its output list to a finite set before taking cardinality. For positive inputs, binaryWord uses the ordinary most-significant-first binary numeral without leading zeros. Its empty list at zero is a totalization outside the published positive-input scope, and is not needed for the selected assertion. The accepted axiom closure is propext, Classical.choice and Quot.sound.

Triage

Scope assessment

What the settlement shows

Proved: D5/S1/Words/EndpointShuffleSupport.endpoint_support_eq identifies the entire distinct support with the two-gap rectangle for every natural m. D5/S1/Words/EndpointShuffleSupport.endpointFamily_card proves the rectangle's cardinality, and D5/S1/Words/EndpointShuffleSupport.endpoint_self_shuffle_card gives the exact count (m+1)^2. The decisive mechanism is the recoverability of the two bounded outer gaps, with the middle gap fixed by conservation of zeros.

Proved: D5/S1/Words/EndpointShuffleSupport.binaryWord_pow_add_one connects that word family to every positive exponent. Together with the support theorem, D5/S1/Words/EndpointShuffleSupport.result proves the source's eventual identity with K=1. This is an exact unbounded family, including the boundary k=1; it does not assert a threshold at k=0.

Open here: the other special-input identities posed in A193020 remain separate questions. In particular, the separate plus-two and minus-four questions receive no resolution from this claim. Other binary patterns need their own exhaustive support descriptions; the endpoint-word rectangle alone does not supply them. The selected conclusion can be used wherever this particular plus-one identity is a premise, but gives no automatic change to the entry's other assertions or their truth.

ASSUMED-UNVERIFIED

Unverified assumptions

The external source identity, revision-13 interpretation and literature limits are those of the existing source verification associated with issue 23034 and Library/Digit/layman2011a193020.md; no fresh external source or literature search is asserted here. Later revisions, linked material not read in that scope, worldwide openness and first-publication priority are not certified. The source is credited to John W. Layman and the OEIS contributors under CC-BY-SA-4.0. Only the separate plus-one question is attached to the theorem's resolution claim.

Dossier & anchor history

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