RESEARCH / Focused target
The least self-divisor exponent in OEIS A092028
RELEASED FOUNDATIONS / PROPOSED CONNECTION
Research connections
All source anchors (1)
- The Least Self-Divisor ExponentReleased anchor
Problem
The question
OEIS A092028, NAME (%N, verbatim):
a(n) is the smallest m > 1 such that m divides n^m-1
COMMENTS (%C, verbatim; Farideh Firoozbakht, Mar 26 2004):
Conjecture 1: All terms of this sequence are primes.
Conjecture 2: a(n) is the smallest prime factor of n-1 or for n>2, A092028(n) = A020639(n-1).
The literal formal claim is ∀ n > 2, a(n) = minFac(n − 1), where
a(n) = sInf {m ∈ ℕ | 1 < m ∧ m ∣ n^m − 1}. In the natural numbers,
sInf ∅ = 0; for every n > 2, the defining set is nonempty. Conjecture 1
is a corollary because minFac(n − 1) is prime, and is not formalized as a
separate public theorem.
Motivation
Our foothold
The equality identifies the least solution of a self-referential divisibility condition for every natural input above two. It proves the unbounded OEIS conjecture rather than extending the entry's finite data.
Gap
Missing bridges
The searches recorded in preregistration issue #7526 and its probe on
2026-09-13 found that OEIS history entries #1 through #16, including revision
#16, still carry both conjectures. The sibling plus-sign entry A092067 was
proved by Neder in 2019; it supplied a search pattern only and is not imported.
Exact searches returned MathOverflow 0, Crossref 0, and GitHub issues 0.
arXiv, Semantic Scholar, and OpenAlex were rate-limited, while GitHub code
search was unauthenticated. Those unavailable surfaces are
ASSUMED-UNVERIFIED. The completed searches are bounded and establish no
priority claim.
Route
Proposed approach
For the upper bound, let p = minFac(n − 1). The number p is prime and
p ∣ n − 1, hence n^p ≡ 1 (mod p) and p belongs to the defining set.
For the lower bound, take any m > 1 with m ∣ n^m − 1 and let
q = minFac(m). The multiplicative order of (n : ZMod q) divides both m
and q − 1. Minimality of q gives gcd(m, q − 1) = 1, so the order is one.
Thus q ∣ n − 1, and minFac(n − 1) ≤ q ≤ m. Together the two bounds give
the claimed equality.
Falsifier
What would falsify this route
One natural number n > 2 for which the least m > 1 dividing n^m − 1
differs from minFac(n − 1) would contradict the theorem.
Evidence
Evidence to collect
- Lean module:
D5/S3/Arith/Congruence/FiroozbakhtLeastSelfDivisorPowerMinusOne.lean. - Main theorem:
firoozbakht_a092028. - Axioms: std3 (
propext,Classical.choice,Quot.sound). - The orchestrator checked every
nwith3 ≤ n ≤ 3000and found zero mismatches. - The probe checked all 9998 cases with
3 ≤ n ≤ 10000and found zero mismatches. Forn = 3..12, the values are2, 3, 2, 5, 2, 7, 2, 3, 2, 11.
Triage
Scope assessment
theorem. The formal result proves the equality for every natural n > 2.
ASSUMED-UNVERIFIED
Unverified assumptions
arXiv, Semantic Scholar, and OpenAlex were rate-limited, and GitHub code search was unauthenticated. The successful literature searches were bounded. No claim of exhaustive literature coverage or first-publication priority is made.