RESEARCH / Focused target
Natural orthonormal bases of a dense-square Hilbert evolution algebra
RELEASED FOUNDATIONS / PROPOSED CONNECTION
Research connections
All source anchors (1)
Problem
The question
Kaygorodov, Martin Gonzalez and Viruel, Evolution algebras: a survey of results and a list of open problems, arXiv:2610.22248v1, section 2.2.8, Question 46 (page 26), ask:
If the square of a Hilbert evolution algebra is dense, is its natural orthonormal basis unique up to permutation and unimodular scalars?
The assertion quantifies over real or complex complete separable Hilbert spaces, bilinear products with bounded left multiplication for every fixed vector, and two complete natural orthonormal bases indexed by the positive integers. The algebraic square is the linear span of all pair products; density means norm density. Completeness of a basis means closed linear span equal to the Hilbert space. The following sentence about derivations, automorphisms and spectral theory is excluded.
Motivation
Our foothold
The condition that all products span densely need not distinguish individual basis squares. A pair of equal nonzero squares can retain an orthonormal rotation while the remaining squares generate a dense subspace. The interaction between these two facts is the source of nonuniqueness.
Gap
Missing bridges
The Hilbert realization framework is in arXiv:2012.05124v2, Definition 2.2 and Corollary 2.4. The algebraic table is Example 3.7 of arXiv:2505.14584v1. The equal-square rotation mechanism is in arXiv:2311.08387v2, Examples 3.6-3.7. These are credited ingredients. The latter examples alone have square in a proper closed coordinate hyperplane and do not provide a dense square. Combining the table, complete Hilbert realization, dense product span and complete nonmonomial natural basis is the assertion considered here.
Route
Proposed approach
Take $H=\ell^2(\mathbb N_{>0},\mathbb C)$ and its standard Hilbert basis $(e_i)$. Define the complex-bilinear product on all of $H\times H$ by [ \mu(x,y)=x_1y_1e_1+\sum_{i\ge2}x_iy_ie_{i-1}. ] The uniformly bounded coordinate bilinear maps and the two-two Holder pairing give a norm-convergent series and a continuous bilinear map. For each $v$, the strictly positive constant $|\mu(v,\cdot)|+1$ is a left-multiplication bound for every $w$.
The table is $e_1^2=e_2^2=e_1$ and $e_{i+1}^2=e_i$, with zero mixed products. Put [ f_1=\tfrac35e_1+\tfrac45e_2,\qquad f_2=-\tfrac45e_1+\tfrac35e_2,\qquad f_i=e_i\quad(i\ge3). ] The block and its inverse preserve orthonormality and closed span. Equality of the first two squares cancels the only potentially nonzero mixed product in the changed block. Every $e_i$ is a square, so the algebraic product span is norm dense. The vector $f_1$ has two nonzero standard coordinates and cannot be a scalar multiple of any single $e_j$. Thus every permutation and every unimodular scalar family fails at index one. A complex counterexample refutes the real-or-complex universal claim.
Falsifier
What would falsify this route
A failure of complete orthonormality, norm convergence, bilinearity, a left-multiplication bound, naturality for either full basis, norm density of the algebraic square, or the exclusion of any proposed identification would invalidate the counterexample. Replacing a Hilbert basis by a finite or Hamel basis, or postulating density or continuity, would not establish this assertion.
Evidence
Evidence to collect
The formal endpoint is
D5/S3/QuadraticForms/EvolutionAlgebras/HilbertNaturalBasisNonuniqueness.result.
Its literal type is the negation of claim. The definition claim is the
conjunction of the real and complex universal uniqueness assertions.
The proof uses the stronger complex counterexample. The accepted axiom
boundary is the closure contained in propext, Classical.choice and
Quot.sound. The public definitions e, mu and f over the explicit lp carrier
identify the complete witness; the private analytic and coordinate arguments discharge
all its hypotheses.
Triage
Scope assessment
What the settlement shows
- Proved:
D5/S3/QuadraticForms/EvolutionAlgebras/HilbertNaturalBasisNonuniqueness.resultrefutes the whole first interrogative for the stated real-or-complex class by a complex counterexample. The complex universal assertion is a consequence of the full conjunction, not an equivalent reformulation. - Proved within that result: the equal nonzero first two basis squares permit the displayed orthogonal block. Bilinearity cancels its mixed product, while every standard vector remains a square. This is the mechanism by which norm density coexists with distinct complete natural orthonormal bases; it is not a separate theorem or additional resolution.
- Computed: no numerical or finite-search conclusion is used. The rational coefficients are exact, and the infinite-dimensional analytic premises are discharged in the Lean proof.
- Surviving boundary: the result refutes uniqueness from dense square alone; it supplies no uniqueness theorem under additional independence hypotheses on basis squares. That strengthened direction remains open here.
- Effect: a claim relying on uniqueness cannot obtain that premise solely from density of the algebraic square. The present result does not classify derivations, automorphisms or spectra; the next sentence of Question 46 remains open here, and no other survey question is included.
- Eligible successor: none is established or selected. The independence direction above has no separately verified external question or complete admission basis in this unit and receives no separate problem count.
ASSUMED-UNVERIFIED
Unverified assumptions
The bounded source and literature checks identified no prior published whole answer. Citation closure and semantic coverage of all literature remain incomplete because of citation-service rate limits and indexing limitations. No global absence, construction-discovery or priority claim is made. The algebraic table, Hilbert realization and equal-square rotation method are attributed to their existing sources.