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RESEARCH / Focused target

Wilf Classes of Rotation Avoidance for Patterns of Length Four

Literature status: not recheckedRepository record: proved

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Problem

The question

Ömer Eğecioğlu, Collier Gaiser and Mei Yin, Pattern avoidance in permutations and their rotations, arXiv:2607.20750v1, Section 6, Open Question 6.1: for k ≥ 4, are the Wilf classes of S_n^{(k)}(q), the permutations of [n] whose first k rotations all avoid q, over the patterns q ∈ S_4 exactly the eight complement–reverse orbits? Writing a(n,k;q) for the number of such permutations, the statement is: for every k ≥ 4 and q, s ∈ S_4, a(n,k;q) = a(n,k;s) for every n ≥ k if and only if s lies in the orbit of q under complement and reverse.

Motivation

Our foothold

The theorem D5/S3/Combinatorics/RotationAvoidance/RotationAvoidance.result establishes the equivalence for every k ≥ 4 and every pair of patterns of length four, so rotation avoidance has exactly the eight classes represented by 1234, 1243, 1324, 1342, 1423, 1432, 2143 and 2413.

Gap

Missing bridges

Pre-registration issue 12488 records the literature screen: the arXiv record has only version 1, author pages and title searches show no answer, and the repository had no claim on it. This is a bounded negative finding.

Route

Proposed approach

  1. Complement and reverse preserve a(n,k;q), which gives the direction from orbits to equal counts.
  2. For k ∈ {n − 1, n}, a(n,k;q) reduces to counting circular arrangements and words with a unique bad cut, so the counts for k ≥ 4 are governed by the cases k = n and k = n − 1.
  3. An endpoint test classifies the bad cuts, and exact normal forms describe the unique-bad-cut words for seven orbit representatives; contraction at consecutive endpoints reduces the remaining slices.
  4. The resulting counts involve the classes Av(213, 231), Av(132, 213), Av(231, 2134, 4213), Av(213, 4132) and Av(123, 3412), counted by 2^{n−1}, 2^n − n, odd-index Fibonacci numbers and an explicit shuffle formula.
  5. Five uniform strict inequalities for n ≥ 7, together with small n, separate every pair of distinct orbits.

Falsifier

What would falsify this route

The classification would fail if two distinct orbits had equal counts for every n ≥ k at some k ≥ 4, or if a bad cut escaped the endpoint test.

Evidence

Evidence to collect

An exhaustive enumeration of a(n,k;q) for all q ∈ S_4, k ≥ 4 and n ≤ 12 agrees with the formulas, and an independent referee implementation checked the endpoint test and normal forms on the same range.

Triage

Scope assessment

theorem; the statement is Open Question 6.1 of arXiv:2607.20750v1, quantified over every k ≥ 4 and every pair of patterns of length four.

  • Proved (formalized): exactly eight Wilf classes, the complement–reverse orbits, for every k ≥ 4.
  • Proved (formalized): exact counts of unique-bad-cut words for the eight representatives and the counts |Av_n(213, 4132)| = F_{2n−1}, |Av_n(231, 2134, 4213)| = 2^n − n.
  • Open: the analogous classification for patterns of length five and for 1 ≤ k ≤ 3.

ASSUMED-UNVERIFIED

Unverified assumptions

The literature screen is limited to the arXiv record of arXiv:2607.20750, author pages, web and GitHub searches and the repository checks.

Dossier & anchor history

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