RESEARCH / Focused target
Wilf Classes of Rotation Avoidance for Patterns of Length Four
RELEASED FOUNDATIONS / PROPOSED CONNECTION
Research connections
All source anchors (1)
- D5/S3/Combinatorics/RotationAvoidance/RotationAvoidance.resultAbsent from this graph
Problem
The question
Ömer Eğecioğlu, Collier Gaiser and Mei Yin, Pattern avoidance in permutations and their rotations, arXiv:2607.20750v1, Section 6, Open Question 6.1: for k ≥ 4, are the Wilf classes of S_n^{(k)}(q), the permutations of [n] whose first k rotations all avoid q, over the patterns q ∈ S_4 exactly the eight complement–reverse orbits? Writing a(n,k;q) for the number of such permutations, the statement is: for every k ≥ 4 and q, s ∈ S_4, a(n,k;q) = a(n,k;s) for every n ≥ k if and only if s lies in the orbit of q under complement and reverse.
Motivation
Our foothold
The theorem D5/S3/Combinatorics/RotationAvoidance/RotationAvoidance.result establishes the equivalence for every
k ≥ 4 and every pair of patterns of length four, so rotation avoidance has exactly the eight classes represented by
1234, 1243, 1324, 1342, 1423, 1432, 2143 and 2413.
Gap
Missing bridges
Pre-registration issue 12488 records the literature screen: the arXiv record has only version 1, author pages and title searches show no answer, and the repository had no claim on it. This is a bounded negative finding.
Route
Proposed approach
- Complement and reverse preserve a(n,k;q), which gives the direction from orbits to equal counts.
- For k ∈ {n − 1, n}, a(n,k;q) reduces to counting circular arrangements and words with a unique bad cut, so the counts for k ≥ 4 are governed by the cases k = n and k = n − 1.
- An endpoint test classifies the bad cuts, and exact normal forms describe the unique-bad-cut words for seven orbit representatives; contraction at consecutive endpoints reduces the remaining slices.
- The resulting counts involve the classes Av(213, 231), Av(132, 213), Av(231, 2134, 4213), Av(213, 4132) and Av(123, 3412), counted by 2^{n−1}, 2^n − n, odd-index Fibonacci numbers and an explicit shuffle formula.
- Five uniform strict inequalities for n ≥ 7, together with small n, separate every pair of distinct orbits.
Falsifier
What would falsify this route
The classification would fail if two distinct orbits had equal counts for every n ≥ k at some k ≥ 4, or if a bad cut escaped the endpoint test.
Evidence
Evidence to collect
An exhaustive enumeration of a(n,k;q) for all q ∈ S_4, k ≥ 4 and n ≤ 12 agrees with the formulas, and an independent referee implementation checked the endpoint test and normal forms on the same range.
Triage
Scope assessment
theorem; the statement is Open Question 6.1 of arXiv:2607.20750v1, quantified over every k ≥ 4 and every pair of
patterns of length four.
- Proved (formalized): exactly eight Wilf classes, the complement–reverse orbits, for every k ≥ 4.
- Proved (formalized): exact counts of unique-bad-cut words for the eight representatives and the counts |Av_n(213, 4132)| = F_{2n−1}, |Av_n(231, 2134, 4213)| = 2^n − n.
- Open: the analogous classification for patterns of length five and for 1 ≤ k ≤ 3.
ASSUMED-UNVERIFIED
Unverified assumptions
The literature screen is limited to the arXiv record of arXiv:2607.20750, author pages, web and GitHub searches and the repository checks.