trureturingGitHub MATHEMATICAL ATLAS

RESEARCH / Focused target

A single-formula feasibility witness for the qubit simplex-and-interval inclusion

Literature status: not recheckedRepository record: proved

RELEASED FOUNDATIONS / PROPOSED CONNECTION

Research connections

0 released anchors
All source anchors (1)

Problem

The question

A. Bluhm, E. Evert, I. Klep, V. Magron and I. Nechita, Inclusion constants for free spectrahedra with applications to quantum incompatibility, arXiv:2512.17706v1, Appendix A.1, conjecture that the explicit tuple with $C_1=(\tfrac1{\sqrt3}-\tfrac12)\begin{pmatrix}1&1\1&1\end{pmatrix}$, the displayed $C_2(\theta)$ and $C_3,\dots,C_6$ from Eq. (47) is feasible for the SDP (37) at $X(\theta)$, $\gamma=4/(1+\sqrt3)$, for every $\theta\in[0,\pi/2]$. The verbatim statements are in the literature note.

Issue #14338 reads "feasible" as membership in $\mathfrak D_{\gamma,X(\theta)}$: all six matrices positive semidefinite in $M_2(\mathbb C)$ and the four affine equations of (37).

Motivation

Our foothold

The SDP (37) certifies that $X(\theta)$ lies in $\gamma,\mathcal W^{\min}(\mathcal D_A(1))$ (the source's prop:HKMFeasibilitySDP), which gives the inclusion constant of the qubit simplex-and-interval free spectrahedron used for joint measurability. Theorem 5.6 proves feasibility with a construction split at $\pi/8$; the conjectured tuple is a single closed formula on the whole interval.

Gap

Missing bridges

The source reduces the conjecture to $\det C_2\ge0$ and states that it could not prove this. Issue #14338 records the literature check before any Lean: only arXiv v1 exists; the citing paper Evert–Graham arXiv:2608.24773 does not treat Appendix A.1; Zenodo has no record; not-found-in-searched-scope.

Route

Proposed approach

With $r=\sqrt3$, $s=\sin\theta$, $c=\cos\theta$, $\beta^2=3((6-4r)s+6c-4r+13)$:

  • the affine equations hold identically because Eq. (47) solves them;
  • $C_1,C_4=(\tfrac1r-\tfrac12)\begin{pmatrix}1&\pm1\ \pm1&1\end{pmatrix}$;
  • $\beta^2=9(c+1)^2+(3s-2r+3)^2$, so $\det C_3=\det C_5=0$ and $\operatorname{tr}C_3=\operatorname{tr}C_5=\beta/6>0$;
  • $144\det C_2=A-B\beta$ with $A=36c+228-96r>0$, $B=16r-12>0$, and $A^2-B^2\beta^2=144(1-s)(219+9s-124r)$, where $219-124\sqrt3>0$; hence $\det C_2\ge0$, and $\operatorname{tr}C_2=(8r-6-\beta)/6>0$; $C_6$ has the trace and determinant of $C_2$;
  • a real symmetric $2\times2$ matrix with positive trace and nonnegative determinant is positive semidefinite as a complex matrix.

Falsifier

What would falsify this route

The statement concerns the exact tuple of Appendix A.1 and the SDP (37) with $\gamma=4/(1+\sqrt3)$; any other $C_1$, $C_2$ or $\gamma$ is outside the claim. The source's word "positive" for $\det C_2$ is read as nonnegative: $\det C_2=0$ at $\theta=\pi/2$.

Evidence

Evidence to collect

The canonical source is D5/S3/Quantum/Measurement/FreeSpectrahedronFeasibilityWitness.lean, with public claim and result : claim. The axiom closure of result is exactly propext, Classical.choice and Quot.sound; there is no sorry, native_decide or new axiom. The module statement is sha256:8e3161385dc8a9084195f1349f00b18a416e9ae9482194ae863e202c258865ac, the result statement sha256:1079b821c67bfe8e831790fb1d2ca362e7b9bff08ff07a9f3c949bcb05e2ac90 and the claim statement sha256:888093d3ca035627875af0a6ca576c01c5f8fb2d4fab9dc2f6b2331646f6a2cf. The Freeze event is sha256:115351b240dc71bb8eefa8f6aca18156a9f3b9c011aa80f0659d0db50da365b7; its project-level prerequisite is D5/S3/Constants/Radicals/SqrtThreeThreshold (frozen node sha256:eff322ff7062275040292c230faf45c194bb5d0cfc0f2d7a6aaa4cf65fc216c5, module statement sha256:7772994aef5132c9610ed05ed595937b5ac5ac22b1cde9f80ba34f2c5f87a10b), whose three_lt_two_mul_sqrt_three gives $\sqrt3>3/2$.

Triage

Scope assessment

Tier 1 conjecture of a December 2025 paper, preregistered in issue #14338 before any Lean. theorem; resolution proved.

| declaration | proof_shape | escape_witness | admission_basis | | --- | --- | --- | --- | | result | content | scalar_bounds: $A-B\beta\ge0$ from $A^2-B^2\beta^2=144(1-s)(219+9s-124\sqrt3)$ | open-problem-resolution |

The private helpers posSemidef_of_trace_det (the $2\times2$ criterion), scalar_bounds, affine_eqs and matrix_forms are each used on the proof of result.

Utility is none: the statement holds for every $\theta$ in an interval and is proved by symbolic identities. There is no digestion atom.

What the proof shows

Proved by result: the Appendix A.1 tuple is feasible for every $\theta\in[0,\pi/2]$, so a single closed formula replaces the two-piece construction of Theorem 5.6.

Argued or computed, not formalized.

  • Mechanism. $\beta$ is chosen so that $C_3$ and $C_5$ are rank one for every $\theta$ ($\beta^2=9(c+1)^2+(3s-2r+3)^2$): the tuple stays on the boundary of the positive cone in those two blocks, and the only remaining constraint is the sign of $\det C_2=\det C_6$.
  • Where it is tight. $\det C_2=0$ exactly when $\sin\theta=1$ (the factor $1-s$), so the tuple is on the boundary of the feasible set at $\theta=\pi/2$; elsewhere in $[0,\pi/2)$ $C_2$ and $C_6$ are positive definite.
  • How far the formula extends. Positivity of $C_1,C_3,C_4,C_5$, the identity of the Route and the positivity of $A$, $B$ and $\operatorname{tr}C_2$ hold for every real $\theta$: the radicand of $\beta$ has minimum $13-4\sqrt3-\sqrt{120-48\sqrt3}>0$ over $\theta$, because $(13-4\sqrt3)^2-(120-48\sqrt3)=97-56\sqrt3>0$ ($97^2=9409>9408=3\cdot56^2$); $A\ge192-96\sqrt3>0$; and $\beta^2\le3(13-4\sqrt3+\sqrt{120-48\sqrt3})<(8\sqrt3-6)^2$. Hence the tuple is feasible exactly when $\det C_2\ge0$, that is when $(1-\sin\theta)(219+9\sin\theta-124\sqrt3)\ge0$, i.e. $\sin\theta\ge(124\sqrt3-219)/9\approx-0.4695$.

Open. The source's conjectures on the optimal constant for larger simplices plus an interval (conj:kSimplexPlusLineOptimum) and on four-line incompatibility ($s_\mathbb C(2,4)=2/\sqrt{13}$, conj:fourlines) are not addressed; neither is whether witnesses of this rank-one-block shape exist for them.

Effect on the paper. Theorem 5.6 now has a one-piece certificate; the inclusion constant $\gamma=4/(1+\sqrt3)$ is unchanged.

ASSUMED-UNVERIFIED

Unverified assumptions

The bounded literature check does not establish exhaustive worldwide novelty, priority, or the absence of an independent proof.

Dossier & anchor history

Loading release observations...