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RESEARCH / Focused target

Bergman's Question 19: the field condition in Question 16

Literature status: not recheckedRepository record: refuted

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Problem

The question

Bergman, Thoughts on Eggert's Conjecture, arXiv:1206.0326v2, Contemporary Mathematics 609 (2014), 1–17, Question 16, asks:

Let R be a finite-dimensional nilpotent commutative algebra over an algebraically closed field F, let V be a subspace of R, and let n be a positive integer such that every nonzero element of V has nonzero n-th power. Must dim R ≥ n dim V?

Question 19 explicitly asks whether, for Question 16, algebraic closedness can be dropped or weakened to “F is infinite”. The target is only this field-condition branch, retaining associativity and commutativity. Convention 2 assumes associativity unless explicitly stated otherwise; an identity is not required. All dimensions and all linear structures use the same F.

The affirmative infinite-field assertion is quantified over every infinite field F, every finite-dimensional F-vector space R with an actual F-bilinear multiplication satisfying associativity and commutativity, every linear subspace V, and every positive integer n. Common global nilpotence and nonvanishing n-th powers of every nonzero vector in V are its antecedents. The conclusion is n dim_F V ≤ dim_F R.

| Source clause | Lean counterpart | | --- | --- | | every infinite field | F : Type, [Field F], [Infinite F] | | F-vector space | R : Type, [AddCommGroup R], [Module F R] | | finite dimension | [FiniteDimensional F R] | | F-bilinear multiplication | μ : R →ₗ[F] R →ₗ[F] R | | associativity | ∀ x y z, μ (μ x y) z = μ x (μ y z) | | commutativity | ∀ x y, μ x y = μ y x | | common nilpotence | CommonNilpotent μ | | actual F-linear subspace | V : Submodule F R | | positive exponent | n : ℕ, 0 < n | | all nonzero vectors | ∀ v ∈ V, v ≠ 0 → … ≠ 0 | | n-th power without identity | (List.replicate (n-1) v).foldr (fun x y => μ x y) v | | dimension bound | n * Module.finrank F V ≤ Module.finrank F R | | exact negation | closed claim : Prop, designated result : ¬ claim |

CommonNilpotent μ means that there is k in N such that every list xs of length k and every terminal z have xs.foldr μ z = 0. The terminal is an additional factor: the common vanishing length is k+1, always positive. Under associativity this is global algebra nilpotence, equivalently the corresponding product-span being zero. It is stronger than pointwise nilpotence. For positive n the displayed power has exactly n factors; for n=1 it is v. The closed assertion uses ordinary small carriers, including arbitrary infinite carriers. The counterexample lies in these universes and also refutes the unrestricted mathematical assertion.

Motivation

Our foothold

Over an infinite field a quadratic form can have no nonzero zero while taking values in a one-dimensional space. An annihilating scalar output then separates the dimension of a subspace from the nonvanishing of its squares. A counterexample over Q resolves both the arbitrary-field and infinite-field alternatives as one field-condition question.

Gap

Missing bridges

The algebraically closed hypothesis can force nontrivial zeros of a homogeneous polynomial system; infinitude alone does not. The rational construction realizes this obstruction with associative multiplication and common global nilpotence, with nonvanishing verified for every nonzero vector of V.

Route

Proposed approach

Set F=Q and R=(Q × Q) × Q with the ordinary coordinatewise vector-space structure and the bilinear multiplication

$$ \mu(((a,b),c),((d,e),f))=((0,0),ad+be). $$

LinearMap.mk₂ includes proofs of additivity and scalar linearity in each argument. All outputs lie in the last coordinate, and that line annihilates R. Thus both bracketings of every triple product are zero, proving associativity and common nilpotence with k=2 (three factors). Symmetry gives commutativity. None of these laws is assumed as a countermodel hypothesis.

Let V be the range of the linear injection (a,b) ↦ ((a,b),0). It is a Submodule of dimension two. For every vector in V,

$$ \mu(((a,b),0),((a,b),0))=((0,0),a^2+b^2). $$

The pinned Mathlib result mul_self_add_mul_self_eq_zero over Q shows that a vanishing square forces a=b=0. Therefore all nonzero vectors in V have nonzero square. LinearMap.finrank_range_of_inj and product-space finrank give dim_Q V=2 and dim_Q R=3. At n=2 the claimed conclusion is 4≤3.

Bergman's Example 20, author TeX label E.nonassoc, already supplies the inner-product mechanism. Its graded real algebra has dimensions d,1,d and is explicitly nonassociative; its scalar middle component acts into the third component and its nonvanishing map is cubing. The present multiplication uses the degree-one/degree-two truncation, making the scalar line annihilate everything and hence making the algebra associative. The countermodel uses rational squares. The inner-product mechanism is credited to Bergman; no independent invention of it is claimed.

Falsifier

What would falsify this route

Any omitted infinite-field, finite-dimension, bilinearity, associativity, commutativity, common product-nilpotence, subspace, universal nonzero-vector, positive-exponent or same-field condition invalidates the proposed target match. Reading k=2 as two factors would be an indexing error: it means three factors. Pointwise nilpotence or checks on a finite collection of vectors would not suffice. A prior exact associative settlement would invalidate the open-problem-resolution admission basis, even though the compiled statement remains a mathematical refutation.

Evidence

Evidence to collect

The primary arXiv v2 HTML and author TeX agree on Convention 2, Question 16, Question 19 and Example 20. The author TeX SHA256 is b8a3d395046cc8459a77b5657f6dab8fa37b11af7012ffd0c4f2dd73c9eb80cc. The exact labels and line ranges are in Library/Certificates/bergman2014eggert.md. The author text retains the remark that no examples are known to it without algebraic closedness.

The bounded literature screen inspected arXiv:1309.0053 without locating an answer to this field branch. Repository, pinned-Mathlib and bounded third-party Lean searches supplied no exact result. OpenAlex was rate-limited and a World Scientific prior-work text was inaccessible. The repository's Bergman Question 15 settlement concerns a different question. These findings do not establish worldwide absence of prior work or priority.

The formal evidence is D5/S0/Certificates/Algebra/BergmanInfiniteFieldRefutation.result, whose type is the literal negation of the closed definition claim : Prop. The proof constructs the rational bilinear multiplication and verifies its laws, common nilpotence and nonvanishing squares; it derives the dimension contradiction inside Lean. mul_self_add_mul_self_eq_zero supplies the rational sum-of-squares step, and LinearMap.finrank_range_of_inj and product-space finrank supply the dimensions. The axiom closure consists of Classical.choice, Quot.sound and propext.

Triage

Scope assessment

What the settlement shows

Proved: D5/S0/Certificates/Algebra/BergmanInfiniteFieldRefutation.result refutes the universal infinite-field assertion with an associative, commutative, globally nilpotent rational algebra. This is the field-condition branch of Question 19 attached to Question 16. The same rational model refutes the arbitrary-field alternative; these are one subsidiary question.

The mechanism is anisotropy of a²+b² over Q. The two-dimensional coordinate plane has nonvanishing squares valued in a one-dimensional annihilating line. Making that line annihilate every element forces every triple product to vanish and both associative bracketings to agree. Infinitude alone therefore cannot replace algebraic closedness in the proposed dimension bound. Bergman's Example 20 supplies the inner-product mechanism; its original nonassociative cubing algebra remains distinct from this associative quadratic truncation.

Computed within the Lean proof: the local dimension identities hV and hR are dim_Q V = 2 and dim_Q R = 3. At exponent two the proposed bound is 4 ≤ 3, and norm_num closes the contradiction. These are exact symbolic calculations in result, with no numerical experiment or finite-vector sampling.

Open outside this settlement: Question 16 over algebraically closed fields, the noncommutative branches of Question 19, and Eggert's conjecture. This result changes none of those scopes.

Open successor candidate: for every infinite field F of characteristic other than two admitting an anisotropic binary quadratic form q on F², construct an associative commutative nilpotent algebra R = F² ⊕ F with V = F² ⊕ {0}, nonzero squares on every nonzero vector of V, and dim_F R = 3 < 2 dim_F V = 4. The proposed product uses the symmetric polarization B_q(u,v) = (q(u+v)-q(u)-q(v))/2 in the annihilating last coordinate. This generalization is not established by the delivered theorem. It still needs a Lean construction of the bilinear polarization, its square identity B_q(v,v)=q(v), associativity and commutativity, common three-factor nilpotence, anisotropy-based universal nonvanishing, exact same-field dimensions and the resulting literal refutation. No companion theorem is claimed.

ASSUMED-UNVERIFIED

Unverified assumptions

Worldwide priority and absence of any unlocated earlier exact answer remain unverified. The bounded literature screen and its access limits are stated in Evidence. No originality claim is made for Bergman's inner-product mechanism or for the quadratic construction.

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