RESEARCH / Focused target
Question 6 of Alofi and Dukes: do the stochastically recurrent states of K_{m,n} dominate?
RELEASED FOUNDATIONS / PROPOSED CONNECTION
Research connections
All source anchors (1)
- D5/S3/StatisticalMechanics/Sandpiles/StochasticSandpileBipartiteHalf.resultAbsent from this graph
Problem
The question
In the stochastic sandpile model of Chan, Marckert and Selig, a stable
configuration c on a graph with sink is stochastically recurrent when some
orientation O satisfies in_O(v) ≥ d(v) − c(v) at every non-sink vertex.
For the complete bipartite graph K_{m,n} with the sink in the first part,
Alofi and Dukes (arXiv:2411.02667, Discrete Math. 348 (2025) 114323) record
n^{m−1} m^{n−1} ≤ |Sto(K_{m,n})| ≤ n^{m−1} m^n and ask:
Question 6. Can it be determined whether or not the number of stochastically recurrent states dominates the set of stable states? I.e. can it be decided |Sto(K_{m,n})| ≶ n^{m−1} m^n / 2 ?
Motivation
Our foothold
D5/S3/StatisticalMechanics/Sandpiles/StochasticSandpileBipartiteHalf.result
proves 2 |Sto(K_{m,n})| ≤ n^{m−1} m^n for all m ≥ 2, n ≥ 1, with
equality if and only if m = 2: the stochastically recurrent states never
dominate.
Gap
Missing bridges
Issue #10704 preregisters the readings, the proof route and the literature
check. The paper itself characterises Sto(K_{2,n}), and Selig and Zhu
(arXiv:2409.11811) characterise the stochastically recurrent configurations of
K_{m,n}, but neither compares their number with half of the stable
configurations; the citing work found does not address the question.
not-found-in-searched-scope.
Route
Proposed approach
- Every orientation directs each of the
mnedges into exactly one vertex, so the in-degrees sum tomn; summingin_O(v) + c(v) ≥ d(v)over the non-sink vertices gives at least2mn − n − mn = n(m − 1)grains. - The involution
c(v) ↦ d(v) − 1 − c(v)sendsSgrains to(m − 1)(2n − 1) − S, so it maps{S ≥ n(m − 1)}injectively into the disjoint set{S ≤ (m − 1)(n − 1)}. - For
m = 2an explicit orientation makes every configuration withngrains recurrent, and the involution exchanges{S ≥ n}and{S ≤ n − 1}; form ≥ 3a configuration withn(m − 1) − 1grains lies in neither set.
Falsifier
What would falsify this route
The answer would fail if some recurrent configuration had fewer than
n(m − 1) grains, or if for m ≥ 3 twice the number of recurrent states
reached the number of stable configurations.
Evidence
Evidence to collect
Exhaustive computation over all orientations gives |Sto| / stable equal to
1/2, 4/8, 12/24, 32/64 for m = 2, n = 1, …, 4, and 1/3, 13/36, 90/243, 486/1296, 1/4, 38/128, 537/1728 for (m, n) = (3,1), (3,2), (3,3), (3,4), (4,1), (4,2), (4,3); the same computation reproduces the paper's
Sto(K_{2,2}) of Example 5 (issue #10704).
The canonical source is
D5/S3/StatisticalMechanics/Sandpiles/StochasticSandpileBipartiteHalf.lean.
Its public declarations are IsOrientation, indeg, Stable, Sto,
claim and result, with a decidability instance for the adjacency of
completeBipartiteGraph. The frozen module state has statement identity
sha256:66f9ad3d071bc39d873b66cc43e41f00625debb75434a7432e49587ff0db6650.
The result declaration has statement identity
sha256:827b40093a749c2657980b8969d6ebec5300dd42054f7d2fe3de021f15f50ea4.
The Freeze event is
sha256:3585da88b101e48f3eafcc690d23e52d5324d800a13e4b0073dc1e484cceae7c.
It has no project-level frozen prerequisite. The proof uses only the standard
axioms propext, Classical.choice and Quot.sound; no sorry,
native_decide, or new axiom.
Triage
Scope assessment
Tier 1 external named open problem, preregistered in issue #10704 before the
probe. theorem; resolution proved. The public theorem has
proof_shape: content: the lower bound on the grains of a recurrent
configuration and the involution count are new propositions on the live proof
path. Its admission basis is open-problem-resolution; utility none.
ASSUMED-UNVERIFIED
Unverified assumptions
The bounded literature check does not establish exhaustive worldwide novelty, priority, or the absence of an independent proof.