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Beluhov's invariant-kernel dimension conjecture fails at type (1,3,6)

Over the rational-function field Q(a,b,c), the proper Gale--Robinson type (1,3,6) has at least six independent elements in its parity-gauge invariant kernel. Beluhov's Conjecture 3 predicts five.

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Refutation at type (1,3,6)

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Beluhov's invariant-kernel dimension conjecture fails at type (1,3,6)Beluhov's invariant-kerneldimension conjecture fails attype (1,3,6)
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